Question

Задача по химии масса цинка=65 грамм+ соединение HCl,масса продукта H2=1,2 гр.Найти Vпр.(H2) Пожалуйста срочно помогите,совсем ничего не понимаю

Answer 1

Дано:
m(H₂)=1,2г.
Vm=22,4л./моль
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V(H₂)-?
Эта задача решается очень просто, потому что дан продукт в граммах и нужно найти его объем. Vm=22,4л./моль - это молярный объем любого газа,( при нормальных условиях 1моль любого газа занимает объем 22,4л.)
Решение:
1. Определим молярную массу водорода: M(H₂)=1x2=2г./моль
2. Определим количество вещества водорода в его 1,2г.(есть формула зависимости количества вещества массы и молярной массы):
n=m÷M    n(H₂)=m(H₂)÷M(H₂)=1,2г.÷2г./моль=0,6моль
3. Определяем объем водорода количеством вещества 0,6мол. по формуле:
 V(H₂)=n(H₂)×Vm = 0,6моль×22,4л./моль=13,44л.
4. Ответ: водород массой 1.2 г. это объем водорода 13,44л.

Answer 2

Task Solution:

To solve the problem, we can use the given information to find the volume of hydrogen gas produced.

Given: - Mass of zinc (Zn) = 65 grams - Compound: HCl - Mass of product (H2) = 1.2 grams

First, we need to find the moles of zinc (Zn) using its molar mass, and then use the stoichiometry of the reaction to find the moles of hydrogen gas (H2). Finally, we can use the ideal gas law to find the volume of hydrogen gas produced.

1. Calculate Moles of Zinc (Zn): - The molar mass of zinc (Zn) is approximately 65.38 g/mol. - Using the given mass of zinc (65 grams), we can calculate the moles of zinc.

2. Use Stoichiometry to Find Moles of Hydrogen Gas (H2): - The balanced chemical equation for the reaction between zinc and hydrochloric acid (HCl) is: `Zn + 2HCl -> ZnCl2 + H2` - From the balanced equation, we can see that 1 mole of zinc produces 1 mole of hydrogen gas. - Therefore, the moles of hydrogen gas produced will be the same as the moles of zinc used.

3. Find Volume of Hydrogen Gas (H2) Using Ideal Gas Law: - The ideal gas law is given by the equation: `PV = nRT`, where - P = pressure - V = volume - n = moles of gas - R = ideal gas constant - T = temperature

- Given that the pressure, temperature, and ideal gas constant are not provided, we can use the ideal gas constant (R = 0.0821 L·atm/(K·mol)) at standard temperature and pressure (STP) for the calculation.

- We can rearrange the ideal gas law to solve for V (volume): `V = (nRT) / P` - At STP, the pressure (P) is 1 atm and the temperature (T) is 273 K.

- Using the moles of hydrogen gas (H2) and the ideal gas constant, we can calculate the volume of hydrogen gas produced.

Conclusion:

The volume of hydrogen gas (H2) produced can be calculated using the given mass of zinc and the mass of the product (H2). By following the steps outlined above, you can find the volume of hydrogen gas produced in this reaction.