Question

Какой объем C2H2 выделится при взаимодействии с водой 100 г. CaC2, содержащего 10% примесей? Помогите пожалуйста!

Answer 1

Решение есть на фотографии

Answer 2

Calculating the Volume of C2H2 Released from the Reaction

To calculate the volume of C2H2 released when 100g of CaC2, containing 10% impurities, reacts with water, we can use the following steps:

1. Calculate the Actual Mass of CaC2: - The actual mass of CaC2 is 100g minus 10% of impurities, which is 10g. - Therefore, the actual mass of CaC2 is 90g.

2. Determine the Moles of CaC2: - We can use the molar mass of CaC2 to determine the moles of CaC2. - The molar mass of CaC2 is 64.1 g/mol.

   n(CaC2) = m(CaC2) / M(CaC2) = 90g / 64.1g/mol ≈ 1.404 moles
   

3. Use the Stoichiometry of the Reaction: - The balanced chemical equation for the reaction of CaC2 with water is: CaC2 + 2H2O → C2H2 + Ca(OH)2.

   1 mole of CaC2 produces 1 mole of C2H2
   

4. Calculate the Volume of C2H2: - We can use the ideal gas law to calculate the volume of C2H2 produced. - The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol.

   V(C2H2) = n(C2H2) * 22.4 L/mol
   

Conclusion

The volume of C2H2 released when 100g of CaC2, containing 10% impurities, reacts with water is approximately 31.5 liters.