Question

Очень срочно нужно расставить коэффициенты методом электронного баланса: 1) MnSO4+KMnO4+KOH=K2MnO4+K2SO4+H2O; 2) NaCrO2+Br2+NaOH=NaBr+Na2CrO4+H2O … 13 минут тому. NaOH+HCL=NaCL+H2O Решите уравнение Расставьте коэффициенты Пожалуйста.

Answer 1

Решение во вложении ---------

Answer 2

Balancing Chemical Equations using the Electron Balance Method

To balance the given chemical equations using the electron balance method, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each equation step by step:

Equation 1: MnSO4 + KMnO4 + KOH = K2MnO4 + K2SO4 + H2O

To balance this equation, we can follow these steps:

Step 1: Start by balancing the atoms that appear in only one compound on each side of the equation. In this case, we have Mn, S, K, and O.

Step 2: Balance the atoms of Mn by adding a coefficient of 2 in front of KMnO4 and K2MnO4.

2KMnO4 + MnSO4 + 2KOH = K2MnO4 + K2SO4 + H2O

Step 3: Balance the atoms of S by adding a coefficient of 2 in front of K2SO4.

2KMnO4 + MnSO4 + 2KOH = K2MnO4 + 2K2SO4 + H2O

Step 4: Balance the atoms of K by adding a coefficient of 4 in front of KOH.

2KMnO4 + MnSO4 + 4KOH = K2MnO4 + 2K2SO4 + H2O

Step 5: Balance the atoms of O by adding a coefficient of 5 in front of H2O.

2KMnO4 + MnSO4 + 4KOH = K2MnO4 + 2K2SO4 + 5H2O

Therefore, the balanced equation is:

2KMnO4 + MnSO4 + 4KOH = K2MnO4 + 2K2SO4 + 5H2O

Now let's move on to the second equation.

Equation 2: NaCrO2 + Br2 + NaOH = NaBr + Na2CrO4 + H2O

To balance this equation, we can follow these steps:

Step 1: Start by balancing the atoms that appear in only one compound on each side of the equation. In this case, we have Na, Cr, O, Br, and H.

Step 2: Balance the atoms of Na by adding a coefficient of 2 in front of NaOH and NaBr.

NaCrO2 + Br2 + 2NaOH = 2NaBr + Na2CrO4 + H2O

Step 3: Balance the atoms of Cr by adding a coefficient of 2 in front of Na2CrO4.

NaCrO2 + Br2 + 2NaOH = 2NaBr + 2Na2CrO4 + H2O

Step 4: Balance the atoms of O by adding a coefficient of 4 in front of H2O.

NaCrO2 + Br2 + 2NaOH = 2NaBr + 2Na2CrO4 + 4H2O

Therefore, the balanced equation is:

NaCrO2 + Br2 + 2NaOH = 2NaBr + 2Na2CrO4 + 4H2O

Moving on to the third equation.

Equation 3: NaOH + HCl = NaCl + H2O

To balance this equation, we can follow these steps:

Step 1: Start by balancing the atoms that appear in only one compound on each side of the equation. In this case, we have Na, O, H, and Cl.

Step 2: Balance the atoms of Na by adding a coefficient of 1 in front of NaOH and NaCl.

NaOH + HCl = NaCl + H2O

Step 3: Balance the atoms of O by adding a coefficient of 1 in front of H2O.

NaOH + HCl = NaCl + H2O

Step 4: Balance the atoms of H by adding a coefficient of 1 in front of HCl.

NaOH + HCl = NaCl + H2O

Step 5: Balance the atoms of Cl by adding a coefficient of 1 in front of NaCl.

NaOH + HCl = NaCl + H2O

Therefore, the balanced equation is:

NaOH + HCl = NaCl + H2O

I hope this helps! Let me know if you have any further questions.