Question

Сколько моль фосфора требуется для получения 1,5 моль ортофосфорной кислоты ? Ar( P ) = 31

Answer 1

4P +5O2= 2P2O5

P2O5+3H2O=2H3PO4
для получения 2 моль Н3РО4 нужно 1 моль Р2О5
для полученич 1.5 моль Н3РО4 нужно х моль Р2О5
х=1,5/2=0.75 моль
для получения 2 моль Р2О5 нужно 4 моль Р
для получения 0.75 моль Р2О5 нужно х моль Р
х=0.75×4/2=1.5 моль

Answer 2

Calculating the Amount of Phosphorus Required for Orthophosphoric Acid

To calculate the amount of phosphorus required to produce 1.5 moles of orthophosphoric acid (H3PO4), we can use the balanced chemical equation for the reaction between phosphorus and oxygen to form phosphorus pentoxide (P2O5), which is then hydrated to form orthophosphoric acid.

The balanced chemical equation for the formation of orthophosphoric acid from phosphorus is: 4 P + 5 O2 → 2 P2O5

From this equation, we can see that 4 moles of phosphorus react with 5 moles of oxygen to produce 2 moles of phosphorus pentoxide.

Now, to find the amount of phosphorus required to produce 1.5 moles of orthophosphoric acid, we can use the stoichiometry of the reaction.

Calculation:

Using the stoichiometry of the balanced chemical equation, we can set up a proportion to find the amount of phosphorus required.

1.5 moles of orthophosphoric acid is equivalent to 1.5 moles of phosphorus pentoxide (P2O5), as 1 mole of orthophosphoric acid is formed from 1 mole of phosphorus pentoxide.

From the balanced chemical equation, 2 moles of phosphorus pentoxide are formed from 4 moles of phosphorus.

So, the amount of phosphorus required can be calculated as: 1.5 moles of P2O5 × (4 moles of P / 2 moles of P2O5) = 3 moles of P

Therefore, 3 moles of phosphorus are required to produce 1.5 moles of orthophosphoric acid.

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