Question

Расчитат массовую долю(%)водорода в след.соединениях: а)СН4; б)NH3; в)С2Н2; г)С6Н12О6 С ОБЪЯСНЕНИЕМ ПОЖАЛУЙСТА!!!

Answer 1

а) W(H) = 4 / 16 * 100 % = 25 %
б) W(H) = 3 / 17 * 100 % = 17,6 %
в) W(H) = 2 / 26 * 100 % = 7,6 %
г) W(H) = 12 / 180 * 100 % = 6,6 % 

Answer 2

Calculation of Mass Percentage of Hydrogen in Various Compounds

To calculate the mass percentage of hydrogen in a compound, we need to know the molar mass of the compound and the molar mass of hydrogen. The molar mass of hydrogen is approximately 1.008 g/mol.

Let's calculate the mass percentage of hydrogen in the following compounds:

a) Methane (CH4): Molar mass of methane (CH4) = 12.01 g/mol (carbon) + 4 * 1.008 g/mol (hydrogen) = 16.04 g/mol Mass of hydrogen in methane = 4 * 1.008 g/mol = 4.032 g Mass percentage of hydrogen in methane = (mass of hydrogen / molar mass of methane) * 100% = (4.032 g / 16.04 g/mol) * 100% ≈ 25.17%

b) Ammonia (NH3): Molar mass of ammonia (NH3) = 14.01 g/mol (nitrogen) + 3 * 1.008 g/mol (hydrogen) = 17.03 g/mol Mass of hydrogen in ammonia = 3 * 1.008 g/mol = 3.024 g Mass percentage of hydrogen in ammonia = (mass of hydrogen / molar mass of ammonia) * 100% = (3.024 g / 17.03 g/mol) * 100% ≈ 17.77%

c) Acetylene (C2H2): Molar mass of acetylene (C2H2) = 2 * 12.01 g/mol (carbon) + 2 * 1.008 g/mol (hydrogen) = 26.04 g/mol Mass of hydrogen in acetylene = 2 * 1.008 g/mol = 2.016 g Mass percentage of hydrogen in acetylene = (mass of hydrogen / molar mass of acetylene) * 100% = (2.016 g / 26.04 g/mol) * 100% ≈ 7.74%

d) Glucose (C6H12O6): Molar mass of glucose (C6H12O6) = 6 * 12.01 g/mol (carbon) + 12 * 1.008 g/mol (hydrogen) + 6 * 16.00 g/mol (oxygen) = 180.18 g/mol Mass of hydrogen in glucose = 12 * 1.008 g/mol = 12.096 g Mass percentage of hydrogen in glucose = (mass of hydrogen / molar mass of glucose) * 100% = (12.096 g / 180.18 g/mol) * 100% ≈ 6.72%

In summary, the mass percentages of hydrogen in the given compounds are approximately: a) Methane (CH4): 25.17% b) Ammonia (NH3): 17.77% c) Acetylene (C2H2): 7.74% d) Glucose (C6H12O6): 6.72%

Please note that these values are approximate and may vary slightly depending on the exact molar masses used.