Question

C2h6=c2h5br=c2h5oh=ch3cooc2h5=ch3cooh=ch3cook

Answer 1

C2H6->C2H5Br->C2H5OH->CH3COOC2H5->CH3COOH->CH3COOK

C2H6+Br2=C2H5Br+HBr

C2H5Br+NaOH=C2H5OH+NaBr

C2H5OH + CH3COOH =  CH3COOC2H5 + H2O

СH3COOC2H5 + H2O = CH3COOH + C2H5OH

2CH3COOH+ 2K = 2CH3COOK + H2

Answer 2

The chemical formulas you provided represent different organic compounds. Let's break down each of them:

1. C2H6: This represents ethane, a simple alkane composed of two carbon atoms and six hydrogen atoms.

2. C2H5Br: This represents ethyl bromide (bromoethane), which is an alkyl halide. It has two carbon atoms, five hydrogen atoms, and one bromine atom.

3. C2H5OH: This represents ethanol, the common alcohol we use in beverages and as a solvent. It consists of two carbon atoms, five hydrogen atoms, and one hydroxyl (OH) group.

4. CH3COOC2H5: This represents ethyl acetate, a commonly used solvent. It consists of two carbon atoms, six hydrogen atoms, and an acetate group (CH3COO-) attached to an ethyl group (C2H5-).

5. CH3COOH: This represents acetic acid, a weak acid responsible for the sour taste of vinegar. It consists of two carbon atoms, four hydrogen atoms, and two oxygen atoms.

6. CH3COOK: This represents potassium acetate, which is the potassium salt of acetic acid. It consists of the acetate group (CH3COO-) combined with a potassium ion (K+).

It seems like you've provided a sequence of chemical reactions, starting from ethane (C2H6) and eventually leading to potassium acetate (CH3COOK). However, without the reaction conditions and steps, it's not possible to explain the specific transformations between each compound. If you provide the reaction steps, I can help you understand the process in more detail.