Question

Al(oh)2 - na[al(oh) 4]​

Answer 1

Al(OH)3 + NaOH (p-p)= Na[Al(OH)4]

Answer 2

The chemical formula you provided is incorrect. It seems to be a combination of aluminum hydroxide (Al(OH)2) and sodium tetrahydroxoaluminate ([Al(OH)4]^-Na+), but it's not well-formatted. Let me break it down for you:

1. Aluminum Hydroxide: Al(OH)2 Aluminum hydroxide is a compound formed by the combination of one aluminum ion (Al^3+) and two hydroxide ions (OH^-). The correct formula for aluminum hydroxide is Al(OH)3, not Al(OH)2. Each aluminum ion needs three hydroxide ions to form a stable compound.

2. Sodium Tetrahydroxoaluminate: [Al(OH)4]^-Na+ Sodium tetrahydroxoaluminate is an ion formed when a sodium ion (Na+) combines with a tetrahydroxoaluminate complex ion [Al(OH)4]^-.

Putting it all together, the correct chemical equation involving these compounds would be:

3Na+ + Al(OH)3 -> Na[Al(OH)4]

In this equation, three sodium ions (Na+) react with one molecule of aluminum hydroxide (Al(OH)3) to form one molecule of sodium tetrahydroxoaluminate (Na[Al(OH)4]).