Question

C8H18 → C4H8 → C2H4 → C2H2→ C2H4 → C2H4CL2

Answer 1

C8H18 (t)= C4H10 + C4H8

C4H8 + H2 (t,Pt)= C4H10

C4H10 (t)= C2H6 + C2H4

C2H4 (t,Pd)= C2H2 + H2

C2H2 + H2 (Ni)= C2H4

C2H4 + Cl2 = C2H4Cl2

Answer 2

The sequence you provided represents a series of chemical reactions involving the conversion of a starting compound, C8H18 (octane), to the final compound C2H4Cl2 (1,2-dichloroethane). Let's break down the reactions step by step:

1. C8H18 (octane) → C4H8 (butene): This reaction involves the breaking of carbon-carbon bonds in octane to produce butene, which is a four-carbon alkene.

2. C4H8 (butene) → C2H4 (ethylene): In this reaction, butene undergoes another carbon-carbon bond cleavage to form ethylene, a two-carbon alkene.

3. C2H4 (ethylene) → C2H2 (acetylene): Ethylene is further transformed through a reaction known as dehydrogenation, resulting in the formation of acetylene, a two-carbon alkyne.

4. C2H2 (acetylene) → C2H4 (ethylene): This reaction is an addition reaction where acetylene reacts with hydrogen gas (H2) under appropriate conditions to yield ethylene.

5. C2H4 (ethylene) → C2H4Cl2 (1,2-dichloroethane): The final step involves the chlorination of ethylene, where two chlorine (Cl2) molecules react with ethylene to form 1,2-dichloroethane.

Overall, this sequence represents a series of reactions involving carbon-carbon bond cleavage, hydrogenation, dehydrogenation, and chlorination to convert octane into 1,2-dichloroethane.