Question

СН 3 ОН + К → С 2 Н 5 ОН + CuО → СН 3 ОН + HCI → СН 3 COОН + Na → СН 3 COOН + CaO → СН 3 COОН + Ba(OH) 2 → С 3 Н 7 ОН + CH 3 COOH →

Answer 1

Ответ:

2СН 3 ОН +2 К → CH3OK+H2

С 2 Н 5 ОН + CuО → CH3COH+Cu+H2O

СН 3 ОН + HCI → CH3CL+H2O

2СН 3 COОН + 2Na → 2CH3COONa+H2

2СН 3 COOН + CaO → (CH3COO)2Ca+H2O

2СН 3 COОН + Ba(OH) 2 → (CH3COO)2Ba+2H2O

С 3 Н 7 ОН + CH 3 COOH → CH3COOC3H7+H2O

Объяснение:

Answer 2

Looks like you've provided a series of chemical reactions involving various compounds and elements. However, your representation of the reactions is a bit unclear due to the spacing and formatting. It seems like you're starting with different reactants and going through a sequence of reactions. Let me try to interpret and clarify the reactions for you:

1. CH3OH + K → C2H5OH + CuO
2. CH3OH + HCl → CH3COOH + Na
3. CH3COOH + CaO → CH3COOH + Ba(OH)2
4. CH3COOH + Ba(OH)2 → C3H7OH + CH3COOH

It seems like you're starting with methanol (CH3OH) and going through a series of reactions involving potassium (K), copper oxide (CuO), hydrochloric acid (HCl), sodium (Na), calcium oxide (CaO), and barium hydroxide (Ba(OH)2), ultimately yielding propanol (C3H7OH) and acetic acid (CH3COOH).

If you have any specific questions about these reactions or if you'd like more detailed explanations, please feel free to ask!