Question

(x+3)(x-4)=-10x1=-□x2=□

Answer 1

Ответ:

-1; 2.................

Answer 2

To solve the quadratic equation $(x+3)(x-4) = -10x$, let's first expand the left side of the equation:

$(x+3)(x-4) = x(x-4) + 3(x-4) = x^2 - 4x + 3x - 12$

Now, simplify the equation:

$x^2 - x - 12 = -10x$

Next, move all the terms to one side of the equation to set it equal to zero:

$x^2 - x - 12 + 10x = 0$

Combine like terms:

$x^2 + 9x - 12 = 0$

Now, you have a quadratic equation in the form $ax^2 + bx + c = 0$ with $a = 1$, $b = 9$, and $c = -12$. To solve this quadratic equation, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Plug in the values:

$x = \frac{-9 \pm \sqrt{9^2 - 4(1)(-12)}}{2(1)}$

Now, calculate the discriminant ($b^2 - 4ac$):

$9^2 - 4(1)(-12) = 81 + 48 = 129$

So, the discriminant is 129. Now, use the quadratic formula to find the solutions for (x):

$x = \frac{-9 \pm \sqrt{129}}{2(1)}$

Now, you have two possible solutions:

$x_1 = \frac{-9 + \sqrt{129}}{2}$

$x_2 = \frac{-9 - \sqrt{129}}{2}$

These are the values of $x$ that satisfy the equation $(x+3)(x-4) = -10x$.