Question

22,4 л водню H2 реагує з Фосфором з утворенням сполуки, у якій Фосфор проявляє нижчу валентність. Знайти масу продукту реакції

Answer 1

Відповідь:

Дано:

V(H2)=22,4л

m(PH3)-?

3H2+2P=2PH3

M(PH3)=34г/моль

n(H2)=22,4/22,4=1моль

nH2:nPH3=3:2

n(PH3)=1*2/3=0,67моль

m(PH3)=0,67*34=22,7г

Пояснення:

Answer 2

Reaction between Hydrogen and Phosphorus

When hydrogen gas (H2) reacts with phosphorus (P), it can form a compound in which phosphorus exhibits a lower valency. To find the mass of the reaction product, we need to know the stoichiometry of the reaction. Unfortunately, the provided search snippet does not provide the necessary information about the stoichiometry or the specific compound formed.

To determine the mass of the reaction product, we would need to know the balanced chemical equation for the reaction between hydrogen and phosphorus. This equation would provide the molar ratio between hydrogen and phosphorus, allowing us to calculate the mass of the product based on the given amount of hydrogen.

Without further information, it is not possible to provide a specific answer regarding the mass of the reaction product. If you can provide additional details or the balanced chemical equation for the reaction, I would be happy to assist you further.