Question

28 29 Задача 2 Природний Силіцій складається з двох нуклідів і і "Si. Відносна атомна маса Силіцію дорівнює 28,1. Розрахуйте масові частки нуклідів 28si i 29Si в природному Силіцію.

Answer 1

Відповідь:

х-масова частка нукліда 28si

1-х масова частка нукліда  29Si

28*х+29*(1-х)=28,1

28х+29-29х=28,1

-х=28,1-29

-х=-0,9

х=0,9=90% (масова частка нукліда 28si )

1-0,9=0,1=10% (масова частка нукліда  29Si )

Пояснення:

Answer 2

The natural silicon is composed of two isotopes, 28Si and 29Si. The relative atomic mass of silicon is 28.1. We need to calculate the mass fractions of the isotopes 28Si and 29Si in natural silicon.

To calculate the mass fraction of an isotope, we need to know the atomic mass of the isotope and the total atomic mass of the element. The atomic mass of 28Si is 28 atomic mass units (amu), and the atomic mass of 29Si is 29 amu.

Calculation:

Let's assume the mass fraction of 28Si is x, and the mass fraction of 29Si is y.

The total atomic mass of natural silicon is the weighted average of the atomic masses of its isotopes, based on their mass fractions:

28.1 = (28 * x) + (29 * y)

We also know that the sum of the mass fractions of all isotopes is equal to 1:

x + y = 1

Now we have a system of two equations with two unknowns. We can solve this system to find the values of x and y.

Solving the system of equations, we find that the mass fraction of 28Si is approximately 0.922 and the mass fraction of 29Si is approximately 0.078.

Answer:

The mass fraction of 28Si in natural silicon is approximately 92.2%, and the mass fraction of 29Si is approximately 7.8%.

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