Question

3.Розставити коефіцієнти методом електронного балансу, укажіть процеси окиснення та відновлення, речовини, які є відновником та окисником: CuS + HNO3 = CuSO4 + NO2 + H20​

Answer 1

Відповідь:

CuS + 8HNO3 = CuSO4 + 8NO2 + 4H20​

S⁻²-8e=S⁺⁶║1║відновник

N⁺⁵+1e=N⁺⁴║8║окисник

Пояснення:

Answer 2

Balancing the Equation using the Method of Electron Balance

To balance the given chemical equation using the method of electron balance, we need to ensure that the number of electrons gained in the reduction half-reaction is equal to the number of electrons lost in the oxidation half-reaction.

The given equation is:

CuS + HNO3 = CuSO4 + NO2 + H2O

Let's balance the equation step by step:

Step 1: Identify the oxidation and reduction half-reactions.

In this equation, CuS is being oxidized to CuSO4, and HNO3 is being reduced to NO2.

Step 2: Balance the atoms other than hydrogen and oxygen.

The atoms other than hydrogen and oxygen are Cu, S, N, and O.

The number of Cu atoms is already balanced on both sides.

The number of S atoms is already balanced on both sides.

The number of N atoms is already balanced on both sides.

The number of O atoms is 3 on the left side (from HNO3) and 6 on the right side (from CuSO4 and H2O). To balance the oxygen atoms, we need to add 3 water molecules (H2O) to the left side.

The equation now becomes:

CuS + HNO3 = CuSO4 + NO2 + 3H2O

Step 3: Balance the hydrogen atoms.

The number of hydrogen atoms is 1 on the left side (from HNO3) and 6 on the right side (from 3H2O). To balance the hydrogen atoms, we need to add 6 H+ ions to the left side.

The equation now becomes:

CuS + HNO3 + 6H+ = CuSO4 + NO2 + 3H2O

Step 4: Balance the charges.

The charge on the left side is 0 (since CuS is neutral), and the charge on the right side is +2 (from CuSO4) and +4 (from NO2). To balance the charges, we need to add 2 electrons (2e-) to the left side.

The equation now becomes:

CuS + HNO3 + 6H+ + 2e- = CuSO4 + NO2 + 3H2O

Step 5: Verify the balance of atoms and charges.

On the left side, we have 1 Cu, 1 S, 1 N, 9 H, and 2e-. On the right side, we have 1 Cu, 1 S, 1 N, 9 H, and 2e-. The atoms and charges are balanced.

Summary of the Balanced Equation

The balanced equation using the method of electron balance is:

CuS + HNO3 + 6H+ + 2e- = CuSO4 + NO2 + 3H2O

In this equation, CuS is oxidized to CuSO4, and HNO3 is reduced to NO2. The reducing agent (or the substance that is oxidized) is CuS, and the oxidizing agent (or the substance that is reduced) is HNO3.

Please let me know if you need any further clarification or have any other questions!