Question

Дописати рівняння реакцій . Срочно!!! 1) K + O2 =2) Al + O2 =3) Zn + O2 = 4) N2 + O2 = 5) W + O2 = 6) P + O2 = 7) Cl2 + O2 = 8) B + O2 = 9) Ba + O2 = 10) S + O2 = ​

Answer 1

Ответ:

1) K2O

2) Al2O3

3) ZnO

4)N2O5

5)WO3

6)P2O5

7)Cl2O7

8)B2O3

9)BaO

10)SO3

невпевнена, але попробуй

Answer 2

Balancing Chemical Equations

Sure! I can help you balance these chemical equations. Here are the equations you provided:

1) K + O2 = 2) Al + O2 = 3) Zn + O2 = 4) N2 + O2 = 5) W + O2 = 6) P + O2 = 7) Cl2 + O2 = 8) B + O2 = 9) Ba + O2 = 10) S + O2 =

Let's go through each equation and balance them one by one.

1) K + O2 = To balance this equation, we need to make sure that the number of atoms on both sides of the equation is equal. Since there is only one potassium (K) atom on the left side, we need to put a coefficient of 2 in front of K to balance the equation. The balanced equation is:

2K + O2 =

2) Al + O2 = To balance this equation, we need to balance the number of aluminum (Al) atoms and oxygen (O2) molecules. Since there is only one aluminum atom on the left side, we need to put a coefficient of 2 in front of Al to balance the equation. The balanced equation is:

2Al + O2 =

3) Zn + O2 = To balance this equation, we need to balance the number of zinc (Zn) atoms and oxygen (O2) molecules. Since there is only one zinc atom on the left side, we need to put a coefficient of 2 in front of Zn to balance the equation. The balanced equation is:

2Zn + O2 =

4) N2 + O2 = To balance this equation, we need to balance the number of nitrogen (N2) molecules and oxygen (O2) molecules. Since there is only one nitrogen molecule on the left side, we need to put a coefficient of 2 in front of N2 to balance the equation. The balanced equation is:

2N2 + O2 =

5) W + O2 = To balance this equation, we need to balance the number of tungsten (W) atoms and oxygen (O2) molecules. Since there is only one tungsten atom on the left side, we need to put a coefficient of 3 in front of W to balance the equation. The balanced equation is:

3W + O2 =

6) P + O2 = To balance this equation, we need to balance the number of phosphorus (P) atoms and oxygen (O2) molecules. Since there is only one phosphorus atom on the left side, we need to put a coefficient of 4 in front of P to balance the equation. The balanced equation is:

4P + O2 =

7) Cl2 + O2 = To balance this equation, we need to balance the number of chlorine (Cl2) molecules and oxygen (O2) molecules. Since there is only one chlorine molecule on the left side, we need to put a coefficient of 7 in front of Cl2 to balance the equation. The balanced equation is:

7Cl2 + O2 =

8) B + O2 = To balance this equation, we need to balance the number of boron (B) atoms and oxygen (O2) molecules. Since there is only one boron atom on the left side, we need to put a coefficient of 3 in front of B to balance the equation. The balanced equation is:

3B + O2 =

9) Ba + O2 = To balance this equation, we need to balance the number of barium (Ba) atoms and oxygen (O2) molecules. Since there is only one barium atom on the left side, we need to put a coefficient of 2 in front of Ba to balance the equation. The balanced equation is:

2Ba + O2 =

10) S + O2 = To balance this equation, we need to balance the number of sulfur (S) atoms and oxygen (O2) molecules. Since there is only one sulfur atom on the left side, we need to put a coefficient of 2 in front of S to balance the equation. The balanced equation is:

2S + O2 =

I hope this helps! Let me know if you have any further questions.