Question

СРОЧНО ВИРУЧИТЕ!!!!! [при спалюванні 13.8 г. органічної речовини утворилось 26.4 вуглекислого газу і 16.2 г. води відносна густина пари речовини за вуглекислим газом дорівнює 1.0455. введіть молекулярну формулу речовини]​

Answer 1

m(орг. в-ва) = 13.8 g

m(CO2) = 26.4 g

m(H2O) = 16.2 g

D за CO2(орг. в-ва) = 1.0455

орг. в-во - ?

n(CO2) = 26.4 g / 44 g / mol = 0.6 mol

n(H2O) = 16.2 g / 18 g / mol = 0.9 mol

органические вещества состоят из атомов "органогенов" (N, O, C, H ...) в связи с тем что при сгорании получился углекислый газ и вода сделаем вывод что там могут быть лишь C и H либо C, H , O :

n(C) = 0.6 mol * 1 = 0.6 mol ; m(C) = 0.6 mol * 12 g / mol = 7.2 g ;

n(H) = 0.9 mol * 2 = 1.8 mol ; m(H) = 1.8 mol * 1 g / mol = 1.8 g ;

масса вещества - это сумма масс всех атомов в нём, потому:

m(орг.в-ва) = 13.8 g ; 7.2 g + 1.8 g = 9 g ; 13.8 != 9 , тут есть ещё O:

m(O) = 13.8 g - 9 g = 4.8 g ; n(O) = 4.8 g / 16 g / mol = 0.3 mol

n(C):n(H):n(O) = 0.6:1.8:0.3 | / 0.3 = 2:6:1

C2H6O ;

Ответ: этиловый спирт либо по изомерии диметиловый эфир .

Answer 2

Molecular Formula Calculation for Organic Compound

To calculate the molecular formula of the organic compound, we can use the given information about the combustion of 13.8 g of the organic substance, which produced 26.4 g of carbon dioxide and 16.2 g of water. Additionally, the relative density of the vapor of the substance to carbon dioxide is 1.0455.

First, we need to find the moles of carbon dioxide and water produced in the combustion reaction. Then, we can use this information to determine the empirical formula of the organic compound. Finally, we can calculate the molecular formula using the molar mass of the compound.

Calculation Steps

1. Calculate Moles of Carbon Dioxide and Water - Moles of carbon dioxide (CO2) = Mass of CO2 / Molar mass of CO2 - Moles of water (H2O) = Mass of H2O / Molar mass of H2O

2. Determine Empirical Formula - Find the ratio of moles of carbon and hydrogen in the compound by dividing the moles of carbon and hydrogen by the smallest number of moles obtained.

3. Calculate Molecular Formula - Use the molar mass of the empirical formula to calculate the molecular formula.

Calculation Results

Let's calculate the moles of carbon dioxide and water first.

- Moles of carbon dioxide (CO2) = 26.4 g / 44.01 g/mol = 0.6 moles - Moles of water (H2O) = 16.2 g / 18.02 g/mol = 0.9 moles

Next, we can determine the empirical formula using the moles of carbon and hydrogen.

- The ratio of moles of carbon to hydrogen is 0.6 : 0.9, which simplifies to 2 : 3.

Now, we can calculate the molecular formula using the relative density of the vapor of the substance to carbon dioxide, which is 1.0455.

Given that the relative density of the vapor of the substance to carbon dioxide is 1.0455, we can use this information to determine the molecular formula. However, without additional information about the composition of the organic compound, it's not possible to determine the specific molecular formula.

If you have additional information about the composition of the organic compound, please provide it so that we can further assist you in determining the molecular formula.

If you have any other questions or need further assistance, feel free to ask!