Question

Определите объемные доли газов в смеси полученной при смешивании 5 л азота и 15 л водорода

Answer 1

Дано:

V(N2)= 5 л

V(H2) =15 л

Найти:

φ-?

Решение:

1) 5 л+15 л= 20 л= объём смеси

φ = Vгаза/ Vсмеси*100%

объёмная доля азота = 5/20 *100%=25%

объёмная доля водорода = 15/20 *100%=75%

Answer 2

Gas Mixture Volume Calculation

To determine the volumetric composition of the gas mixture obtained by combining 5 liters of nitrogen and 15 liters of hydrogen, we can calculate the volume percentages of each gas in the mixture.

The volume percentage of a gas in a mixture can be calculated using the following formula:

Volume Percentage of Gas A = (Volume of Gas A / Total Volume of Mixture) * 100

Let's calculate the volume percentages of nitrogen and hydrogen in the given mixture.

Volume Percentage of Nitrogen: Volume of Nitrogen = 5 liters Total Volume of Mixture = 5 liters (nitrogen) + 15 liters (hydrogen) = 20 liters Volume Percentage of Nitrogen = (5 / 20) * 100 = 25%

Volume Percentage of Hydrogen: Volume of Hydrogen = 15 liters Total Volume of Mixture = 5 liters (nitrogen) + 15 liters (hydrogen) = 20 liters Volume Percentage of Hydrogen = (15 / 20) * 100 = 75%

Therefore, the volumetric composition of the gas mixture obtained by combining 5 liters of nitrogen and 15 liters of hydrogen is: - Nitrogen: 25% - Hydrogen: 75%