Question

Определить объем SO3 в 19 гр пж пж пж помогите

Answer 1

n(SO3) = m/M = 19 г/80 г/моль = 0,2375 (моль)

V(SO3) = Vm × n = 22,4 см³/моль × 0,2375 моль = 5,32 (см³)

Ответ: 5,32 см³

Answer 2

Calculating the Volume of SO3 in 19g

To calculate the volume of SO3 in 19g, we can use the given information to determine the volume. The molar volume of a gas at standard temperature and pressure (STP) is 22.4 liters. We can use this information to calculate the volume of SO3 in 19g.

The molar mass of SO3 is 80.06 g/mol. Using this information, we can calculate the number of moles of SO3 in 19g.

Step 1: Calculate the number of moles of SO3 in 19g The number of moles can be calculated using the formula: \[ \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

Substituting the given values: \[ \text{moles} = \frac{19g}{80.06g/mol} \approx 0.2374 \text{ moles} \]

Step 2: Calculate the volume of SO3 at STP At STP, the molar volume of a gas is 22.4 liters/mol. We can use this information to calculate the volume of SO3.

\[ \text{Volume} = \text{moles} \times \text{molar volume at STP} \] \[ \text{Volume} = 0.2374 \text{ moles} \times 22.4 \text{ liters/mol} \approx 5.32 \text{ liters} \]

Therefore, the volume of SO3 in 19g at STP is approximately 5.32 liters.