Question

яка маса алюмінію вступить в реакцію з хлоридною кислотою, якщо при цьому утвориться 13,35 г алюміній хлориду?

Answer 1

x г - 13,35 г

$2Al + 6HCl = 2AlCl3 + 3H2$

n=2 моль n=2 моль

М=27 г/моль М = 133,5 г/моль

m=54 г m =267 г

х г Al - 13,35 г AlCl3

54 г Al - 267 г AlCL3

m(Al) = 54 • 13,35/267 = 2,7 г

Answer 2

Aluminum Reaction with Hydrochloric Acid

When aluminum reacts with hydrochloric acid, it forms aluminum chloride and hydrogen gas. The balanced chemical equation for this reaction is:

2 Al + 6 HCl → 2 AlCl3 + 3 H2

This equation shows that 2 moles of aluminum react with 6 moles of hydrochloric acid to produce 2 moles of aluminum chloride and 3 moles of hydrogen gas.

Calculating the Mass of Aluminum

To calculate the mass of aluminum that will react with a given amount of hydrochloric acid to produce a specific mass of aluminum chloride, we can use the stoichiometry of the reaction.

Given: - Mass of aluminum chloride formed = 13.35 g - Balanced chemical equation: 2 Al + 6 HCl → 2 AlCl3

From the balanced chemical equation, we can see that 2 moles of aluminum react with 6 moles of hydrochloric acid to produce 2 moles of aluminum chloride. This means that the molar ratio of aluminum to aluminum chloride is 2:2, or simply 1:1.

Using the molar mass of aluminum (26.98 g/mol) and aluminum chloride (133.34 g/mol), we can calculate the mass of aluminum that will react to form 13.35 g of aluminum chloride.

Calculation

1. Calculate the number of moles of aluminum chloride formed: - Moles of AlCl3 = Mass of AlCl3 / Molar mass of AlCl3 - Moles of AlCl3 = 13.35 g / 133.34 g/mol - Moles of AlCl3 ≈ 0.1 moles

2. Since the molar ratio of aluminum to aluminum chloride is 1:1, the moles of aluminum that will react is also approximately 0.1 moles.

3. Calculate the mass of aluminum that will react: - Mass of Al = Moles of Al × Molar mass of Al - Mass of Al = 0.1 moles × 26.98 g/mol - Mass of Al ≈ 2.698 g

Therefore, approximately 2.698 grams of aluminum will react with hydrochloric acid to produce 13.35 grams of aluminum chloride.