
Срочно обчисліть яка маса гідроксиду цинку може прореагувати з розчином який містить 2,94 г
сульфатної кислоти!!!!

Ответы на вопрос

Дано:
m(H2SO4) = 2,94 г
Найти:
m(Zn(OH)2) - ?
Решение:
Zn(OH)2 + H2SO4(р-р) => ZnSO4 + 2H2O
n=m/M
M(H2SO4) = 2 × 1 + 1 × 32 + 4 × 16 = 98 г/моль
n(H2SO4) = 2,94 / 98 = 0,03 моль
n(Zn(OH)2) = n(H2SO4) = 0,03 моль
m=n×M
M(Zn(OH)2) = 1 × 65 + 2 × 16 + 2 × 1 = 99 г/моль
m(Zn(OH)2) = 0,03 × 99 = 2,97 г
Ответ: 2,97 г



Calculating the Mass of Zinc Hydroxide Reacting with Sulfuric Acid
To calculate the mass of zinc hydroxide that can react with a given amount of sulfuric acid, we can use the stoichiometry of the balanced chemical equation for the reaction between zinc hydroxide and sulfuric acid.
The balanced chemical equation for the reaction is: Zn(OH)2 + H2SO4 → ZnSO4 + 2H2O
From the balanced equation, we can see that 1 mole of zinc hydroxide reacts with 1 mole of sulfuric acid.
Given: Mass of sulfuric acid = 2.94 g
To find the mass of zinc hydroxide that can react with this amount of sulfuric acid, we can follow these steps:
1. Convert the mass of sulfuric acid to moles. 2. Use the mole ratio from the balanced chemical equation to find the moles of zinc hydroxide. 3. Convert the moles of zinc hydroxide to mass.
Step 1: Convert the Mass of Sulfuric Acid to Moles
The molar mass of sulfuric acid (H2SO4) is 98.08 g/mol.Using the formula: moles = mass / molar mass
We can calculate the moles of sulfuric acid: moles = 2.94 g / 98.08 g/mol = 0.03 moles
Step 2: Use the Mole Ratio to Find the Moles of Zinc Hydroxide
From the balanced chemical equation: 1 mole of zinc hydroxide reacts with 1 mole of sulfuric acid.So, the moles of zinc hydroxide that can react with the given moles of sulfuric acid is also 0.03 moles.
Step 3: Convert the Moles of Zinc Hydroxide to Mass
The molar mass of zinc hydroxide (Zn(OH)2) is 99.38 g/mol.Using the formula: mass = moles * molar mass
We can calculate the mass of zinc hydroxide: mass = 0.03 moles * 99.38 g/mol = 2.98 g
Therefore, the mass of zinc hydroxide that can react with the given amount of sulfuric acid (2.94 g) is approximately 2.98 grams.


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