Question

Na + O2 → II Ni + O2 → III P + O2 → Si + O2 → C3H4 + O2 → II NH3 +O2 → C4H8 + O2 → C6H6 + O2 → C2H2 + O2 → V PH3 + O2 →

Answer 1

4Na + O2 --> 2Na2O

4Ni + 3O2 --> 2Ni2O3

4P + 5O2 --> 2P2O5

Si + O2 --> SiO2

2C3H4 + 5O2 ---> 6CO + 4H2O

4NH3 + 3O2 --> 2N2 + 6H2O

C4H8 + 6O2 --> 4CO2 + 4H2O

2C6H6 + 30O2 --> 12CO2 + 6H2O

2C2H2 + 5O2 --> 4CO2 + 2H2O

2PH3 + 4O2 --> P2O5 + 3H2O

Answer 2

The balanced chemical equations for the given reactions are as follows:

II Na + 1/2 O2 → Na2O III Ni + 1/2 O2 → NiO P4 + 5 O2 → P4O10 Si + O2 → SiO2 C3H4 + 5 O2 → 3 CO2 + 2 H2O II NH3 + 3/2 O2 → N2 + 3 H2O C4H8 + 6 O2 → 4 CO2 + 4 H2O C6H6 + 15 O2 → 6 CO2 + 3 H2O C2H2 + 2 1/2 O2 → 2 CO2 + H2O V PH3 + 5/2 O2 → P2O5 + 3 H2O

Please note that the Roman numerals (II, III, and V) indicate the oxidation states of the elements in those particular reactions.