Question

а)Fe(OH)3----->Fe2O3+H2O b)Ca3(PO4)2---->CaO+P2O5 c)HNO3---->H2O+NO2+O2 d)Cu(NO3)2---->CuO+NO2+O2 NOMER2 a)Li+O2---> b)Al+O2---> c)Fe+Cl2---->FeCl3 d)Fe+H2O+O2--->Fe(OH)3 RESHITE POZHALUSTO

Answer 1

 №1

1)   2Fe(OH)3----->Fe2O3+3H2O . условие протекания - нагревание

2)   3Ca3(PO4)2---->6CaО+P4O10 . условие протекания - не известно об этом соединении

3)   4HNO3---->2H2O+4NO2+O2(+стрелка вверх) . условие протекания - при комнатной температуре, на свету. NO3− + 2H+ + 1e− ==> NO2 + H2O

4)    2Cu(NO3)2---->2CuO+4NO2+O2 . условие протекания - при температуре выше 170* (град.)

№2 

1)   2Li2+O2 ==> О2 + 4Li

2)   4Al+3O2 ==> 2Al2O3

3)   2Fe+3Cl2---->2FeCl3 . условие протекания - при температуре выше 170* (град.)

4)   4Fe+6H2O+3O2--->4Fe(OH)3 . условие протекания - не известны об том соединении.

Answer 2

1)а)2Fe(OH)3 = Fe2O3 + 3H2O

 б)2Ca3(PO4)2 = P4O10 + 6CaO

 с)4HNO3= 4NO2 + 2H2O + O2↑
д)2Cu(NO3)2 = 2CuO + 4NO2 + O2

2)O2 + 4Li = 2Li2O

   4Al + 3O2 = 2Al2O3

   3Cl2 + 2Fe = 2FeCl3

 4Fe + 3O2 + 6H2O = 4Fe(OH)3

Answer 3

a) Fe(OH)3 → Fe2O3 + H2O Iron(III) hydroxide decomposes to form iron(III) oxide and water.

b) Ca3(PO4)2 → CaO + P2O5 Calcium phosphate decomposes to form calcium oxide and phosphorus pentoxide.

c) HNO3 → H2O + NO2 + O2 Nitric acid decomposes to form water, nitrogen dioxide, and oxygen.

d) Cu(NO3)2 → CuO + NO2 + O2 Copper(II) nitrate decomposes to form copper(II) oxide, nitrogen dioxide, and oxygen.

NOMER2:

a) 4Li + O2 → 2Li2O Four lithium atoms react with oxygen to form two lithium oxide molecules.

b) 4Al + 3O2 → 2Al2O3 Four aluminum atoms react with three oxygen molecules to form two aluminum oxide molecules.

c) 2Fe + 3Cl2 → 2FeCl3 Two iron atoms react with three chlorine molecules to form two iron(III) chloride molecules.

d) 4Fe + 6H2O + 3O2 → 4Fe(OH)3 Four iron atoms react with six water molecules and three oxygen molecules to form four iron(III) hydroxide molecules.

Please note that chemical reactions should be balanced, meaning the number of atoms of each element should be the same on both sides of the equation.