Question

KCrO2 + Br2 + KOH → K2CrO4 + KBr + H2O.

Answer 1

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Answer 2

The given chemical equation represents the reaction between potassium chromate(II) (KCrO2), bromine (Br2), and potassium hydroxide (KOH) to form potassium chromate(VI) (K2CrO4), potassium bromide (KBr), and water (H2O).

The balanced chemical equation for the reaction is as follows:

2 KCrO2 + 2 Br2 + 2 KOH → K2CrO4 + 2 KBr + H2O

This equation shows that two moles of potassium chromate(II), two moles of bromine, and two moles of potassium hydroxide react to produce one mole of potassium chromate(VI), two moles of potassium bromide, and one mole of water.