Question

KOH + Cr2O3 → KCrO2 + H2O​

Answer 1

Объяснение:

2 KOH + Cr2O3 → H2O + 2 KCrO2

Answer 2

The balanced chemical equation for the reaction between potassium hydroxide (KOH) and chromium(III) oxide (Cr2O3) to form potassium chromate (KCrO2) and water (H2O) is as follows:

6 KOH + Cr2O3 → 2 KCrO2 + 3 H2O

In this reaction, 6 moles of KOH react with 1 mole of Cr2O3 to produce 2 moles of KCrO2 and 3 moles of water. The reaction requires a 6:1 mole ratio of KOH to Cr2O3 to obtain the correct stoichiometry.