Question

P2O5 + ... = Ca3(PO4)2 + H2O​

Answer 1

Ответ:

Объяснение:

P2O5 + 3Ca(OH)2 = Ca3(PO4)2 + 3H2O​

Answer 2

Reply by Kolokokosik

Реакция ниже

P2O5 + 3Ca(OH)2 ==> Ca3(PO4)2 + 3H2O​

Answer 3

To balance the chemical equation, we need to determine the coefficients for each compound. The unbalanced equation is:

P2O5 + ___ = Ca3(PO4)2 + H2O

Let's balance it step by step:

First, let's balance the phosphorus (P) atoms. On the left side, we have 2 P atoms in P2O5, and on the right side, we have 2 P atoms in Ca3(PO4)2. This means the phosphorus atoms are already balanced.

Next, let's balance the calcium (Ca) atoms. On the left side, we have no calcium atoms, and on the right side, we have 3 Ca atoms in Ca3(PO4)2. To balance the calcium atoms, we need a coefficient of 3 in front of Ca3(PO4)2:

P2O5 + ___ = 3 Ca3(PO4)2 + H2O

Now let's balance the oxygen (O) atoms. On the left side, we have 5 O atoms in P2O5, and on the right side, we have 2 O atoms in Ca3(PO4)2 and 1 O atom in H2O. In total, we have 2 + 1 = 3 O atoms on the right side. To balance the oxygen atoms, we need a coefficient of 3/5 in front of H2O:

P2O5 + ___ = 3 Ca3(PO4)2 + (3/5) H2O

Now, let's balance the hydrogen (H) atoms. On the left side, we have no hydrogen atoms, and on the right side, we have (3/5) H2O molecules, which means we have (3/5) * 2 = 6/5 hydrogen atoms. To balance the hydrogen atoms, we need a coefficient of 6/5 in front of H2O:

P2O5 + ___ = 3 Ca3(PO4)2 + (6/5) H2O

To make the coefficients integers, we can multiply all coefficients by 5 to eliminate the fractions:

5 P2O5 + ___ = 15 Ca3(PO4)2 + 6 H2O

Finally, to balance the equation, we need to place a coefficient of 15 in front of P2O5:

15 P2O5 + ___ = 15 Ca3(PO4)2 + 6 H2O

Therefore, the balanced chemical equation is:

15 P2O5 + ___ = 15 Ca3(PO4)2 + 6 H2O