Question

осуществите превращение mn-mno-mn(oh)²-mncl²-mn(no³)²​

Answer 1

2Mn+O2=>2MnO

MnO+H2O=>Mn(OH)2

Mn(OH)2+2HNO3=>Mn(NO3)2+2H2O

Answer 2

2 Mn-MnO-Mn(OH)2-MnCl2-Mn(NO3)2

Step 1: Balance the equation by adding the appropriate coefficients.
2 Mn + 2 MnO + 4 Mn(OH)2 + 2 MnCl2 + 4 Mn(NO3)2 → 6 Mn + 2 MnO2 + 16 H2O + 2 Cl2 + 8 NO2

Step 2: Identify the oxidation states of each element and the changes involved.
Mn: +2 → +7
O: -2 → -1
H: +1 → 0
Cl: -1 → 0
N: +5 → +4

Step 3: Break the equation down into half-reactions for oxidation and reduction.
Oxidation: Mn → MnO2 + 4e-
Reduction: 8H+ + 8NO3- + 3MnO + 12e- → 3Mn2+ + 16H2O + 8NO2

Step 4: Balance the half-reactions by adding the appropriate coefficients.
Oxidation: Mn → MnO2 + 4e-
Reduction: 24H+ + 24NO3- + 9MnO + 36e- → 9Mn2+ + 72H2O + 24NO2

Step 5: Multiply the oxidation half-reaction by 9 and combine the two half-reactions to cancel out the electrons.
9Mn → 9MnO2 + 36e-
24H+ + 24NO3- + 9MnO + 36e- → 9Mn2+ + 72H2O + 24NO2
-----------------------
24H+ + 24NO3- + 9Mn + 27MnO2 → 18Mn2+ + 72H2O + 24NO2

Step 6: Check that the equation is balanced for mass and charge.
9 Mn-MnO-Mn(OH)2-MnCl2-Mn(NO3)2 → 18 Mn2+ + 24 NO2 + 72 H2O + 2 Cl2

The final balanced equation is:
9 Mn-MnO-Mn(OH)2-MnCl2-Mn(NO3)2 → 18 Mn2+ + 24 NO2 + 72 H2O + 2 Cl2