Question

C3H6+HBr= C2H6+HBr= CH4+HBr=

Answer 1

1)С3Н7Br
2)этан не может присоединять,
3)метан тоже не реагирует с НВг(тока с галогенами-замещение)

Answer 2

The given chemical equations are:

1. C3H6 + HBr → C2H6 + H2C=CH2Br
2. C2H6 + HBr → CH3CH2Br + H2
3. CH4 + HBr → CH3Br + H2

In the first equation, C3H6 reacts with HBr to form C2H6 and H2C=CH2Br. This reaction involves the addition of HBr to the carbon-carbon double bond of C3H6, which results in the formation of a bromonium ion intermediate. The bromonium ion is then attacked by a hydrogen ion, resulting in the formation of H2C=CH2Br and protonated HBr. The protonated HBr then loses a proton to form HBr.

In the second equation, C2H6 reacts with HBr to form CH3CH2Br and H2. This reaction also involves the addition of HBr to the carbon-carbon double bond of C2H6, which forms a bromonium ion intermediate. The bromonium ion is then attacked by a molecule of C2H6 to form the product CH3CH2Br and a protonated C2H6. The protonated C2H6 then loses a proton to form H2.

In the third equation, CH4 reacts with HBr to form CH3Br and H2. This reaction involves the substitution of a hydrogen atom in CH4 by a bromine atom from HBr. The reaction proceeds through a radical mechanism, where the hydrogen atom is first abstracted from CH4 by a bromine radical, resulting in the formation of a methyl radical and HBr. The methyl radical then reacts with another molecule of HBr to form the product CH3Br and a hydrogen radical. The hydrogen radical then reacts with another molecule of HBr to form H2.