Question

Al->Al2(SO4)3->Al(OH)3->x1->Al(NO3)3

Answer 1

Al2(SO4)3 + 2H2O = 2Al(OH)SO4 + H2SO4 (молекулярное)
Al3+ + H2O = Al(OH)2+ + H+ (сокращенное ионное) .
Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4
Al(NO3)3 + 4KOH = KAlO2 + 3KNO3 + 2H2O
Al(OH)3 + KOH = KAlO2 + 2H2O)

Answer 2

The given sequence represents a chemical reaction that starts with aluminum (Al) and proceeds through several intermediate steps to form aluminum nitrate (Al(NO3)3) as the final product.

The intermediate steps involve the following reactions:

1. Aluminum reacts with sulfuric acid to form aluminum sulfate: Al + H2SO4 → Al2(SO4)3 + H2

2. Aluminum sulfate reacts with water to form aluminum hydroxide: Al2(SO4)3 + 6H2O → 2Al(OH)3 + 3H2SO4

3. Aluminum hydroxide reacts with an unknown compound (x1) to form aluminum nitrate: 2Al(OH)3 + x1 → Al(NO3)3 + 3H2O

The overall balanced equation for the entire reaction sequence is:

2Al + 3H2SO4 + 6H2O + x1 → Al(NO3)3 + 3H2SO4 + 6H2O

or simply:

2Al + 3H2SO4 + x1 → Al(NO3)3 + 3H2O

Note that sulfuric acid (H2SO4) is both a reactant and a product in this reaction sequence. This means that it acts as a catalyst and is not consumed in the reaction.