Question

AL2(SO4)3→ALCL3→AL(OH)3

Answer 1

1)  Al2(SO4)3+3BaCl2=2AlCl3+3BaSO4
2)  AlCl3+3H2O=Al(OH)3+3HCI

Answer 2

Al2 (SO4) 3+BaCl2=AlCl3+BaSO4↓ AlCl3+3NaOH=Al(OH)3↓+3NaOH

Answer 3

The given chemical equation represents a series of reactions involving aluminum sulfate (Al2(SO4)3), aluminum chloride (AlCl3), and aluminum hydroxide (Al(OH)3). Let's break down each step of the reaction:

1. Aluminum Sulfate (Al2(SO4)3): Al2(SO4)3 is the initial compound in the reaction. It consists of two aluminum ions (Al3+) and three sulfate ions (SO4^2-).

2. Aluminum Chloride (AlCl3): In the first step, Al2(SO4)3 reacts with an appropriate reagent, such as hydrochloric acid (HCl), to produce aluminum chloride (AlCl3). The reaction can be represented as follows: Al2(SO4)3 + 6HCl → 2AlCl3 + 3H2SO4 In this reaction, the aluminum sulfate reacts with hydrochloric acid, yielding aluminum chloride and sulfuric acid (H2SO4).

3. Aluminum Hydroxide (Al(OH)3): In the next step, aluminum chloride (AlCl3) reacts with water (H2O) to form aluminum hydroxide (Al(OH)3): AlCl3 + 3H2O → Al(OH)3 + 3HCl Here, the aluminum chloride reacts with water, producing aluminum hydroxide and hydrochloric acid (HCl).

Overall, the series of reactions can be summarized as: Al2(SO4)3 + 6HCl → 2AlCl3 + 3H2SO4 AlCl3 + 3H2O → Al(OH)3 + 3HCl

Please note that these reactions represent a simplified view, and in practical situations, there might be other factors, conditions, or side reactions to consider.