Question

M(P)=31 г m(02)=16 г m(P2O5)-? P+O2=P2O5

Answer 1

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Answer 2

To find the mass of P2O5, we need to use the law of conservation of mass, which states that the mass of the reactants must be equal to the mass of the products in a chemical reaction.

From the given information, we know the following:

• Mass of P (phosphorus) = 31 g
• Mass of O2 (oxygen) = 16 g

The balanced chemical equation for the reaction is:

P + O2 → P2O5

According to the equation, 1 mole of P reacts with 5 moles of O2 to produce 1 mole of P2O5. We can calculate the molar masses of the substances involved:

• Molar mass of P = 31 g/mol
• Molar mass of O2 = 32 g/mol (16 g for each oxygen atom)

Since the stoichiometry of the reaction tells us that 1 mole of P2O5 is formed from 1 mole of P, we can calculate the moles of P2O5 using the given mass of P:

Moles of P = Mass of P / Molar mass of P = 31 g / 31 g/mol = 1 mol

Since the molar ratio of P2O5 to P is 1:1, the moles of P2O5 are also 1.

Now, we can find the mass of P2O5 using its molar mass:

Mass of P2O5 = Moles of P2O5 × Molar mass of P2O5

The molar mass of P2O5 is calculated by summing the molar masses of its constituent elements:

• Molar mass of P = 31 g/mol
• Molar mass of O = 16 g/mol

Molar mass of P2O5 = (2 × Molar mass of P) + (5 × Molar mass of O) = (2 × 31 g/mol) + (5 × 16 g/mol) = 62 g/mol + 80 g/mol = 142 g/mol

Now, we can calculate the mass of P2O5:

Mass of P2O5 = Moles of P2O5 × Molar mass of P2O5 = 1 mol × 142 g/mol = 142 g

Therefore, the mass of P2O5 formed in the reaction is 142 grams.