Question

Какова вероятность рождения здоровых детей если отец гетерозиготен по аутосомному рецессивному заболеванию а мать здорова и гомозиготна

Answer 1

А - здоровый (доминантный признак)
а - больной (рецессивный признак)
Генотип отца - Аа
Генотип матери - АА
       А       А
А    АА     АА
а    Аа      Аа
Все дети будут здоровыми (50% - гомозиготны, 50% - гетерозиготны)

Answer 2

Probability of Having Healthy Children

When the father is heterozygous for an autosomal recessive disease and the mother is healthy and homozygous, the probability of having healthy children can be calculated using Punnett squares and the principles of Mendelian genetics.

The probability of having a healthy child in this scenario is 50% This is because the father's genotype is heterozygous, meaning he carries one copy of the recessive allele and one copy of the dominant allele. The mother, being healthy and homozygous, only carries the dominant allele. When these genotypes are crossed, the Punnett square shows that there is a 50% chance of the child inheriting the dominant allele from the mother, resulting in a healthy phenotype.

In summary, when the father is heterozygous for an autosomal recessive disease and the mother is healthy and homozygous, there is a 50% probability of having healthy children.