Вопрос задан 28.02.2019 в 07:25. Предмет Биология. Спрашивает Яковенко Никита.

Відсутність полових залоз рецесивний алель ,локалізований в х(ікс)-хромосомі.Чоловік у якого

відсутні потові залози ,одружився зі здоровою жінкою ,гетерозиготною за цією ознакою.Визначте ймовірність народження дітей з нормальними потовими залозами
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Отвечает Моряков Максим.
А можешь по-русски написать?
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Absence of Sex Glands and Probability of Children with Normal Sweat Glands

The absence of sex glands is a recessive allele that is localized on the X chromosome. When a man lacks sweat glands due to this allele and marries a healthy woman who is heterozygous for this trait, we can determine the probability of their children having normal sweat glands.

To calculate the probability, we need to consider the inheritance pattern of the trait and the genotypes of the parents.

Inheritance Pattern and Genotypes

The absence of sweat glands is caused by a recessive allele, which means that an individual must have two copies of the allele to express the trait. Let's assign the following genotypes:

- Man (husband): XY (normal sweat glands) - Woman (wife): XaX (carrier of the recessive allele)

The X chromosome from the husband will always be passed to his daughters, while the Y chromosome will be passed to his sons. The wife can pass either the X chromosome with the normal allele (X) or the X chromosome with the recessive allele (Xa) to her children.

Probability Calculation

Let's calculate the probability of their children having normal sweat glands:

1. Daughters: The daughters will inherit one X chromosome from their father and one X chromosome from their mother. Since the father has the normal allele (X), all daughters will receive a normal allele for sweat glands. Therefore, the probability of daughters having normal sweat glands is 100%.

2. Sons: The sons will inherit one X chromosome from their mother and one Y chromosome from their father. Since the mother is heterozygous for the trait, there is a 50% chance that she will pass on the normal allele (X) and a 50% chance that she will pass on the recessive allele (Xa). Therefore, the probability of sons having normal sweat glands is 50%.

Conclusion

In summary, the probability of the couple's children having normal sweat glands is 100% for daughters and 50% for sons.

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