Question

AaBb х Aabb Определите фенотип потомства, полученного при скрещивании

Answer 1

Р: ♂️ааВb x ♀️Aabb
G: (aB) (ab) l (Ab) (ab)
F: AaBb (доминантный по двум аллелям), ааBb (рецессивный по аллели а и доминантный по B), Aabb (доминантный по А и рецессивный по b), aabb (рецессивный по двум аллелям)
соотношение по фенотипу 1 : 1 : 1 : 1

Answer 2

To determine the phenotype of the offspring obtained from a cross between AaBb and Aabb individuals, we need to understand the concept of alleles and how they interact.

In this case, let's assume that "A" and "a" are alleles of one gene, and "B" and "b" are alleles of another gene. Each individual has two alleles for each gene, one inherited from each parent.

The possible gametes produced by each parent are as follows:

AaBb parent gametes: AB, Ab, aB, ab Aabb parent gametes: Ab, ab

Now, let's cross the two parents and see what combinations we get:

| AB | Ab | aB | ab |

Ab| AaBb | Aabb | AaBb | Aabb |

ab| AabB | Aabb | Aabb | Aabb |

From the Punnett square above, we can see that there are two possible phenotypes in the offspring:

1. AaBb: This genotype results in the dominant expression of both traits (A and B). The offspring with this genotype will exhibit the dominant phenotypes for both genes.

2. Aabb: This genotype results in the dominant expression of trait "A" but the recessive expression of trait "B". Therefore, the offspring with this genotype will exhibit the dominant phenotype for gene "A" and the recessive phenotype for gene "B."

So, the phenotypes of the offspring obtained from the cross AaBb x Aabb are:

• AaBb: Dominant for both traits
• Aabb: Dominant for trait "A," recessive for trait "B"