
PLEASE HELP ME! How many variants will the AaBbCcDd genome produce if the genes are in different
pairs of homologous chromosomes?1) 42) 83) 124) 14AND HOW YOU SOLVE IT?

Ответы на вопрос

Ответ:
3)12
so because this is



To determine the number of variants produced by a genome with genes on different pairs of homologous chromosomes, we need to consider the principle of independent assortment. Independent assortment states that the alleles of different genes segregate independently of each other during the formation of gametes.
In this case, we have four different gene pairs: A/a, B/b, C/c, and D/d. Each gene pair has two possible alleles, so we multiply the number of alleles for each gene pair together:
2 alleles for gene pair A/a × 2 alleles for gene pair B/b × 2 alleles for gene pair C/c × 2 alleles for gene pair D/d = 2^4 = 16.
Therefore, the AaBbCcDd genome can produce a total of 16 different variants when the genes are in different pairs of homologous chromosomes.
The correct answer would be 16, so none of the options given (42, 8, 12, 14) matches the correct answer.


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