Question

Слово поезд встретилось в корпусе A объёмом 400 тыс. словоформ 5 раз. В корпусе B, объём которого составляет 2 млн словоформ, оно более частотно в относительном измерении. Значит, оно встретилось в корпусе B не менее .... раз. Скажите пожалуйста, не менее скольких раз?

Answer 1

Ответ:

25

Объяснение:

считаешь по калькулятору, это курсы по сириусу сложноваты)

Answer 2

Calculating Frequency of the Word "поезд" in Corpus B

To calculate the frequency of the word "поезд" in corpus B, we can use the relative frequency information provided in the search results.

Given that the word "поезд" appeared 5 times in a corpus A with 400,000 word forms and is more frequent in corpus B, which has 2,000,000 word forms, we can calculate the minimum number of times it appeared in corpus B.

The relative frequency of the word "поезд" in corpus A is 5 / 400,000, and in corpus B, it is more than that.

Using the provided snippet: - In corpus A, the word "поезд" appeared 5 times in 400,000 word forms.

To calculate the minimum number of times the word "поезд" appeared in corpus B, we can use the relative frequency information.

Calculation:

Relative frequency in corpus A = 5 / 400,000 Relative frequency in corpus B > Relative frequency in corpus A

Let's calculate the minimum number of times the word "поезд" appeared in corpus B.

Relative frequency in corpus B = (5 / 400,000) * 2,000,000

Minimum Number of Appearances in Corpus B:

Relative frequency in corpus B = (5 / 400,000) * 2,000,000 = 25

Therefore, the word "поезд" appeared in corpus B not less than 25 times.