Question

Помогите пожалуйста манета подбрасывается 10 раз какова вероятность того что герб выпадет ровно 3 раза

Answer 1

вероятность 50 на 50.потому что не предсказуемо сколько раз она перевернётся в воздухе при подбрасывание

Answer 2

Calculating the Probability of Getting Exactly 3 Heads in 10 Coin Flips

To calculate the probability of getting exactly 3 heads in 10 coin flips, we can use the binomial probability formula. The formula is:

P(X=k) = C(n, k) * p^k * (1-p)^(n-k)

Where: - P(X=k) is the probability of getting exactly k successes (in this case, 3 heads) - C(n, k) is the number of combinations of n items taken k at a time - p is the probability of success on a single trial (in this case, the probability of getting heads) - (1-p) is the probability of failure on a single trial (in this case, the probability of getting tails) - n is the total number of trials (in this case, the number of coin flips)

In this case, we have 10 coin flips and we want to find the probability of getting exactly 3 heads. The probability of getting heads on a single coin flip is 0.5, assuming a fair coin.

Using the formula, we can calculate the probability as follows:

P(X=3) = C(10, 3) * (0.5)^3 * (1-0.5)^(10-3)

Now let's calculate the probability using the formula:

P(X=3) = C(10, 3) * (0.5)^3 * (0.5)^7

To calculate the combination, we can use the formula:

C(n, k) = n! / (k! * (n-k)!)

Let's calculate the combination:

C(10, 3) = 10! / (3! * (10-3)!)

Now let's calculate the probability:

P(X=3) = C(10, 3) * (0.5)^3 * (0.5)^7

Using a calculator, we can find that:

C(10, 3) = 120

P(X=3) = 120 * (0.5)^3 * (0.5)^7

P(X=3) = 120 * 0.125 * 0.0078125

P(X=3) = 0.9375

Therefore, the probability of getting exactly 3 heads in 10 coin flips is approximately 0.9375 or 93.75%.