Question

(2x < 10,(x + 6 > 0​

Answer 1

Это уточнение которое надо решить? Какой ответ вам нужен?

Answer 2

It looks like you have provided two inequalities: $2x < 10$ and $x + 6 > 0$. Let's solve these inequalities separately:

1. $2x < 10$: To solve for $x$, you need to isolate $x$ on one side of the inequality. Divide both sides of the inequality by 2: $x < \frac{10}{2}$ $x < 5$

So, the solution for the first inequality is $x < 5$.

2. $x + 6 > 0$: Subtract 6 from both sides of the inequality: $x > -6$

The solution for the second inequality is $x > -6$.

To find the combined solution, we need to find the range of values that satisfy both inequalities. Since $x$ must be both greater than -6 and less than 5 to satisfy both inequalities, the combined solution is: $-6 < x < 5$

This means that $x$ should be greater than -6 and less than 5 for both inequalities to be simultaneously true.