Question

A=60⁰ BC=10 AC=7 AB=?​

Answer 1

Ответ:

AB=20 HDHDVDHDHJDHDBDHHDUDUSUDJDJJDJDJ

Answer 2

To find the length of side AB in triangle ABC, you can use the Law of Cosines. The Law of Cosines states:

c^2 = a^2 + b^2 - 2ab * cos(C)

Where:

• c is the length of side BC (10 in this case).
• a is the length of side AC (7 in this case).
• b is the length of side AB (which we want to find).
• C is the angle opposite side BC (60 degrees in this case).

Now, plug in the given values:

(10)^2 = (7)^2 + b^2 - 2 * 7 * b * cos(60°)

Now, you can calculate cos(60°):

cos(60°) = 0.5

Now, plug this value back into the equation:

100 = 49 + b^2 - 7b

Subtract 49 from both sides of the equation:

b^2 - 7b + 51 = 0

Now, you can use the quadratic formula to solve for b:

b = (-(-7) ± √((-7)^2 - 4 * 1 * 51)) / (2 * 1)

b = (7 ± √(49 - 204)) / 2

Since the discriminant (the value inside the square root) is negative, there are no real solutions for b. This means that there is no real triangle that can have side lengths AC = 7, BC = 10, and angle C = 60 degrees.