Question

2) x2 – 3x – 10=0.плиз решите уравнение.. ​

Answer 1

Объяснение:

x^2 – 3x – 10=0

Д=9+40=49

Х1=3+7:2=5

Х2=3-7:2=-4:2=-2

Ответ:-2;5

Answer 2

Объяснение:

x^2-3x-10=0

a=1,b=-3,c=-10

D=b^2-4ac

D=9+40=49

x1,2=-b+-√D

---------

2a

x1,2=(3+-7):2

x1=5

x2=-2

Ответ:5;-2

Answer 3

To solve the quadratic equation $x^2 - 3x - 10 = 0$, we can use the quadratic formula, which is given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

where $a$, $b$, and $c$ are the coefficients of the quadratic equation in the form $ax^2 + bx + c = 0$.

For the equation $x^2 - 3x - 10 = 0$, we have $a = 1$, $b = -3$, and $c = -10$. Now, let's substitute these values into the quadratic formula and solve for $x$:

$x = \frac{-(-3) \pm \sqrt{(-3)^2 - 4 \cdot 1 \cdot (-10)}}{2 \cdot 1}$

$x = \frac{3 \pm \sqrt{9 + 40}}{2}$

$x = \frac{3 \pm \sqrt{49}}{2}$

$x = \frac{3 \pm 7}{2}$

Now, we'll have two possible solutions:

1. When $x = \frac{3 + 7}{2} = \frac{10}{2} = 5$
2. When $x = \frac{3 - 7}{2} = \frac{-4}{2} = -2$

So, the solutions to the quadratic equation $x^2 - 3x - 10 = 0$ are $x = 5$ and $x = -2$.