Question

1)3x+1=7 2)5-2x=1 3)5x-2=1 4)-5x-2=-12​

Answer 1

Ответ:

1)3x+1=7 2)5-2x=1

3x=6 2x=4

x=2 x=2

3)5x-2=1 4)-5x-2=-12

5x=3 -5x=-10

x=0,6 x=2

Answer 2

Ответ:

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Answer 3

Let's solve the equations one by one:

1. 3x + 1 = 7

To solve this equation, we need to isolate the variable x. We can start by subtracting 1 from both sides:

3x + 1 - 1 = 7 - 1

3x = 6

Next, we divide both sides by 3 to solve for x:

3x/3 = 6/3

x = 2

Therefore, the solution to the equation 3x + 1 = 7 is x = 2.

2. 5 - 2x = 1

Similarly, let's isolate the variable x. We'll start by subtracting 5 from both sides:

5 - 2x - 5 = 1 - 5

-2x = -4

Next, we divide both sides by -2:

-2x / -2 = -4 / -2

x = 2

The solution to the equation 5 - 2x = 1 is x = 2.

3. 5x - 2 = 1

To solve this equation, let's isolate the variable x. We'll start by adding 2 to both sides:

5x - 2 + 2 = 1 + 2

5x = 3

Next, we divide both sides by 5:

5x / 5 = 3 / 5

x = 3/5

The solution to the equation 5x - 2 = 1 is x = 3/5.

4. -5x - 2 = -12

Let's solve this equation by isolating the variable x. We'll start by adding 2 to both sides:

-5x - 2 + 2 = -12 + 2

-5x = -10

Next, we divide both sides by -5:

-5x / -5 = -10 / -5

x = 2

The solution to the equation -5x - 2 = -12 is x = 2.

Therefore, the solutions to the given equations are:

1. x = 2
2. x = 2
3. x = 3/5
4. x = 2