Question

2x×2+7x+3=0????????? ​

Answer 1

Ответ:

-$\frac{3}{11}$

Объяснение:

Answer 2

It looks like you've provided a quadratic equation. To solve for the value(s) of "x," we can use various methods, such as factoring, completing the square, or using the quadratic formula. In this case, I'll use the quadratic formula:

The quadratic formula states that for an equation of the form ax² + bx + c = 0, the solutions for x are given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In your equation, 2x² + 7x + 3 = 0, we have a = 2, b = 7, and c = 3. Plugging these values into the formula:

$x = \frac{-7 \pm \sqrt{7^2 - 4 \cdot 2 \cdot 3}}{2 \cdot 2}$

Simplifying further:

$x = \frac{-7 \pm \sqrt{49 - 24}}{4}$ $x = \frac{-7 \pm \sqrt{25}}{4}$ $x = \frac{-7 \pm 5}{4}$

Now we have two possible solutions for "x":

1. $x = \frac{-7 + 5}{4} = -\frac{2}{4} = -\frac{1}{2}$
2. $x = \frac{-7 - 5}{4} = -\frac{12}{4} = -3$

So, the solutions to the equation 2x² + 7x + 3 = 0 are $x = -\frac{1}{2}$ and $x = -3$.

Answer 3

It looks like you've provided a quadratic equation: $2x^2 + 7x + 3 = 0$. To solve for $x$, you can use the quadratic formula:

The quadratic formula is: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In your equation, $a = 2$, $b = 7$, and $c = 3$. Plugging these values into the formula:

$x = \frac{-7 \pm \sqrt{7^2 - 4 \cdot 2 \cdot 3}}{2 \cdot 2}$

$x = \frac{-7 \pm \sqrt{49 - 24}}{4}$

$x = \frac{-7 \pm \sqrt{25}}{4}$

$x = \frac{-7 \pm 5}{4}$

This gives you two possible solutions for $x$:

1. $x = \frac{-7 + 5}{4} = -\frac{1}{2}$
2. $x = \frac{-7 - 5}{4} = -3$

So, the solutions to the equation $2x^2 + 7x + 3 = 0$ are $x = -\frac{1}{2}$ and $x = -3$.