Question

4x⁴-5x²+1=025x²+6x=0​

Answer 1

Ответ:

1. 4x⁴ - 5x² + 1 = 0

D = 25 - 4*4 = 25 - 16 = 9

х₁ = (5-3)/2 = 2/2 = 1

х₂ = 8/2 = 4 x² = 1 x = 1 или

x = -1 x² = 4 x = 2

или x = -2

Ответ: -2;-1;1;2  

2. 25x²+6x=0

Х выносим за скобки

Х(25x+6)=0

Х=0 или 25х=-6

                Х= -6/25

Ответ: 0; -6/25 ( дробью)

Объяснение:

Answer 2

It appears that you have two equations:

1. 4x⁴ - 5x² + 1 = 0
2. 25x² + 6x = 0

Let's solve each equation separately:

Equation 1: 4x⁴ - 5x² + 1 = 0

To solve this equation, you can use a substitution to simplify it. Let's make a substitution:

Let y = x². Now, the equation becomes:

4y² - 5y + 1 = 0

Now, you can factor this quadratic equation:

(4y - 1)(y - 1) = 0

Now, you can solve for y:

1. 4y - 1 = 0 → 4y = 1 → y = 1/4
2. y - 1 = 0 → y = 1

Now that you have the solutions for y, you can find the solutions for x:

For y = 1/4: x² = 1/4 x = ±√(1/4) x = ±1/2

For y = 1: x² = 1 x = ±1

So, the solutions for Equation 1 are x = -1/2, x = 1/2, x = -1, and x = 1.

Equation 2: 25x² + 6x = 0

This equation can be factored as follows:

x(25x + 6) = 0

Now, you can solve for x:

1. x = 0
2. 25x + 6 = 0 25x = -6 x = -6/25

So, the solutions for Equation 2 are x = 0 and x = -6/25.

In summary, the solutions to the given system of equations are: For Equation 1: x = -1/2, x = 1/2, x = -1, and x = 1. For Equation 2: x = 0 and x = -6/25.