Question

ПОМОГИТЕ РЕШИТЬ ЗАДАЧУ, СРОЧНО! На вершине горы высотой 3,5 км. барометр показал 720 мм. рт. ст. каково давление у подножья?

Answer 1

Высота горы 3,5 км,давление на вершине 720 мм.рт.ст
3,5 км=3500 метров. Мы знаем,что  при спуске с горы каждые 10-11м(мы берем среднюю величину =10,5 м),давление увеличивается на 1 мм.рт.ст.
В 3500м по 10,5 м будет 3500:10,5=333 раза,следовательно давление у подножья станет  720 мм.рт.ст.+1 мм.рт.ст*333=720+333=1053 мм.рт.ст.

Answer 2

Calculating Pressure Difference

To calculate the pressure difference between the top and the bottom of the mountain, we can use the relationship between pressure and altitude. The pressure at a certain altitude can be calculated using the formula:

P = P0 * e^(-Mgh/RT)

Where: - P is the pressure at the given altitude - P0 is the pressure at sea level - M is the molar mass of Earth's air - g is the acceleration due to gravity - h is the altitude - R is the universal gas constant - T is the temperature

Calculation

Given: - Altitude at the top of the mountain, h = 3.5 km - Pressure at the top of the mountain, P = 720 mmHg - Standard pressure at sea level, P0 = 760 mmHg

We can use the given values to calculate the pressure at the bottom of the mountain using the formula mentioned above.

Solution

Using the formula P = P0 * e^(-Mgh/RT), we can calculate the pressure at the bottom of the mountain.

First, we need to convert the given pressure values to a consistent unit, such as pascals. 1 mmHg is equal to 133.322 pascals.

So, the pressure at the top of the mountain is: P_top = 720 mmHg * 133.322 Pa/mmHg

Now, we can calculate the pressure at the bottom of the mountain using the formula: P_bottom = P_top * e^(Mgh/RT)

Let's calculate the pressure at the bottom of the mountain.