Question

ПЖ ЗДЕЛАЙТЕ ДАЮ 60!!! 1) На висоті 3000м температура становить 2*С (* - градус), атмосферний тиск 415 мм рт.ст. Визначити температуру і тиск біля підніжжя цієї гори.

Answer 1

Ответ:

Объяснение:

При піднятті на 1 км температура знижується на 6°С, тоді маємо

1 км       - 6°

3 км - х°

х = 3 * 6 = 18°

На висоті 3000 м ( - 2°)  , тоді біля підніжжя температура буде

- 2 + 18 = 16°С

На кожні 100 м підйому тиск знижується на 10 мм. рт. ст.

3 * 100 = 300 мм. рт.ст. на стільки зміниться атмосферний тиск з висотою

415 + 300 = 715 мм. рт.ст. атмосферний тиск біля підніжжя цієї гори

Answer 2

Calculation of Temperature and Pressure at the Base of the Mountain

To determine the temperature and pressure at the base of the mountain, we can use the standard atmospheric lapse rate. The lapse rate is the rate at which temperature decreases with an increase in altitude in the Earth's atmosphere.

The standard lapse rate is approximately 6.5 degrees Celsius per kilometer (or 3.6 degrees Fahrenheit per 1,000 feet). However, it's important to note that lapse rates can vary depending on various atmospheric conditions.

Given that the temperature at a height of 3,000 meters is 2 degrees Celsius, we can calculate the temperature at the base of the mountain as follows:

1. Convert the height of 3,000 meters to kilometers: 3,000 meters ÷ 1,000 = 3 kilometers. 2. Multiply the lapse rate of 6.5 degrees Celsius per kilometer by the height in kilometers: 6.5 degrees Celsius/km × 3 km = 19.5 degrees Celsius. 3. Subtract the calculated value from the temperature at the given height: 2 degrees Celsius - 19.5 degrees Celsius = -17.5 degrees Celsius.

Therefore, the temperature at the base of the mountain is approximately -17.5 degrees Celsius.

To determine the pressure at the base of the mountain, we can use the barometric formula, which relates pressure to altitude. The barometric formula is an approximation that assumes a constant temperature lapse rate.

Given that the atmospheric pressure at a height of 3,000 meters is 415 mmHg (millimeters of mercury), we can calculate the pressure at the base of the mountain as follows:

1. Convert the height of 3,000 meters to kilometers: 3,000 meters ÷ 1,000 = 3 kilometers. 2. Multiply the atmospheric pressure at the given height by the exponential of the product of the lapse rate and the height: 415 mmHg × e^(-0.0342 × 3) ≈ 415 mmHg × e^(-0.1026) ≈ 415 mmHg × 0.9023 ≈ 374.8 mmHg.

Therefore, the pressure at the base of the mountain is approximately 374.8 mmHg.

Please note that these calculations are based on the standard lapse rate and the barometric formula, which are simplified models of the Earth's atmosphere. Actual temperature and pressure variations can be influenced by various factors and may deviate from these calculations.