Question

20×a = 568 + 432963 - X= 900 - 579​

Answer 1

Ответ:

1) 20а=568+432

20а=1000

а=1000:20

а=50

2) 963 - х = 900-579

963 - х = 321

-х = 321-963

-х= -642

х=642

P.s если не сложно можете отметить как лучший умоляю и кто списывает можете отблагодарить

Answer 2

It looks like you have a system of equations with two variables: "a" and "X". The equations you've provided are:

1. $20a = 568 + 432963 - X$
2. $X = 900 - 579$

To solve for the values of "a" and "X", we can follow these steps:

Equation 2: $X = 900 - 579$ Simplify the right side: $X = 321$

Now, we can substitute the value of $X$ into Equation 1:

Equation 1: $20a = 568 + 432963 - X$ Substitute $X = 321$: $20a = 568 + 432963 - 321$

Combine the constants: $20a = 433210$

Finally, solve for "a" by dividing both sides by 20: $a = \frac{433210}{20} = 21660.5$

So, the solutions are: $a = 21660.5$ $X = 321$