Question

(2а +с) (а - Зc) +a (2c - а);​

Answer 1

Ответ:

(2a-c)(a-3c)+a(2c-)=2a^2-7ac+3c^2+2ac-a^2=a^2-5ac+3c^2

Answer 2

Объяснение:

2а^2-6ас+ас-3с^2+2ас-а^2= а^2-3ас-3с^2

Answer 3

To simplify the given expression $(2a + c)(a - 3c) + a(2c - a)$, you can use the distributive property (FOIL) and combine like terms. Let's break it down step by step:

1. Expand the terms using FOIL (First, Outer, Inner, Last):

   $$(2a + c)(a - 3c) + a(2c - a)$$

   First: $2a \cdot a = 2a^2$

   Outer: $2a \cdot (-3c) = -6ac$

   Inner: $c \cdot a = ca$

   Last: $c \cdot (-3c) = -3c^2$

   Combine these terms:

   $$2a^2 - 6ac + ca - 3c^2 + a(2c - a)$$

2. Combine like terms:

   Combine the terms with 'a':

   $$2a^2 - 6ac + ca - 3c^2 + 2ac - a^2$$

   Combine the 'a^2' terms:

   $$(2a^2 - a^2) - 6ac + ca + 2ac - 3c^2$$

   Simplify:

   $$a^2 - 4ac - 3c^2$$

So, $(2a + c)(a - 3c) + a(2c - a)$ simplifies to $a^2 - 4ac - 3c^2$.