Question

Срочно Известно, что с высотой в тропосфере атмосферное давление понижается на 1 мм рт.ст. на каждые 10,5 метров. Высота главного здания МГУ в Москве 237 м. Каково атмосферное давление на его шпиле, если у основания здания оно составляет 745 мм рт. ст.? Ответ округлите до целых и запишите в виде числа.Пожалуйста помогите ЗАРАНЕЕ СПАСИБО ❤❤​

Answer 1

237м : 10,5м = 23

745 мм.рт.ст - 23 = 722 мм.рт.ст

Answer 2

Calculating Atmospheric Pressure at the Spire of the Main Building of Moscow State University

To calculate the atmospheric pressure at the spire of the main building of Moscow State University (MSU), we can use the given information about the decrease in atmospheric pressure with altitude in the troposphere.

Given: - Height of the main building of MSU: 237 m - Atmospheric pressure at the base of the building: 745 mm Hg

Using the given information that atmospheric pressure decreases by 1 mm Hg for every 10.5 meters of altitude in the troposphere, we can calculate the atmospheric pressure at the spire of the building.

Calculation: 1. Determine the difference in altitude between the base and the spire of the building: - Altitude difference = Height of spire - Height of base - Altitude difference = 237 m

2. Calculate the change in atmospheric pressure based on the altitude difference: - Pressure change = Altitude difference / 10.5 - Pressure change = 237 / 10.5 - Pressure change ≈ 22.5714 mm Hg

3. Calculate the atmospheric pressure at the spire: - Atmospheric pressure at spire = Atmospheric pressure at base - Pressure change - Atmospheric pressure at spire = 745 - 22.5714 - Atmospheric pressure at spire ≈ 722.4286 mm Hg

Answer: The atmospheric pressure at the spire of the main building of Moscow State University, rounded to the nearest whole number, is approximately 722 mm Hg.