Question

Помоги сделать это задание пожалуйстаJames and John had set their pocket watches to the same time. Unknown to them, John's watch was running exactly two minutes per hour slow, and the watch belonging to James was going exactly a minute per hour too fast. Later, when they checked their watches again, it was discovered that the watch belonging to James was exactly one hour ahead of John's watch. How long had it been since they had originally set their watches?

Answer 1

This case the difference btw John's  and James watches is 3 min per hour. So it had been 60 min/3=20 hours  since they had set their watches

Answer 2

To solve this problem, let's break down the information given:

1. John's watch was running exactly two minutes per hour slow. 2. James's watch was going exactly a minute per hour too fast. 3. Later, when they checked their watches again, James's watch was exactly one hour ahead of John's watch.

Since James's watch was one hour ahead, and John's watch was running two minutes slow per hour, we can conclude that there is a time difference of 62 minutes (60 minutes + 2 minutes).

To find out how long it had been since they originally set their watches, we need to figure out the number of times the two-minute difference occurred.

Let's set up an equation:

62 minutes * x = total elapsed time

Since we are looking for the total elapsed time, let's multiply 62 minutes by the number of times the two-minute difference occurred.

After finding the value of x, we can calculate the total elapsed time.