Question

ПЕРЕВЕДИТЕ What is the pressure applied by an iron cube on the floor? The side length of the cube is 10cm. (Take p 7.9 g/cm3

Answer 1

Какое давление на железный куб на полу? Длина стороны Куба 10см.

Answer 2

Что такое давление, приложенное железным кубом на полу? Длина стороны куба 10 см. (Возьмите р 7,9 г / см3

Answer 3

To calculate the pressure applied by an iron cube on the floor, we need to know the weight of the cube and the area over which the weight is distributed. The pressure is defined as the force applied per unit area.

First, let's calculate the weight of the iron cube. We know the density of iron, which is given as 7.9 g/cm^3. The volume of the cube can be calculated by raising the side length to the power of 3. In this case, the side length is 10 cm.

The volume of the cube is:

Volume = side length^3 = 10 cm^3

Next, we'll calculate the mass of the cube. The mass can be obtained by multiplying the volume by the density:

Mass = Volume * Density = 10 cm^3 * 7.9 g/cm^3

Now, we need to convert the mass to kilograms since the standard unit of weight is Newtons (N), which is derived from kilograms (kg). We can convert grams (g) to kilograms (kg) by dividing by 1000:

Mass = (10 cm^3 * 7.9 g/cm^3) / 1000 = 0.079 kg

The weight of the cube can be calculated using the formula:

Weight = Mass * Acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s^2. Converting the weight to newtons:

Weight = 0.079 kg * 9.8 m/s^2 = 0.7742 N

Now, we have the weight of the cube. To find the pressure, we need to determine the area over which the weight is distributed. Since the cube is resting on the floor, we can assume that the entire bottom surface of the cube is in contact with the floor.

The area of the bottom surface is equal to the side length squared:

Area = side length^2 = 10 cm^2 = 0.01 m^2

Finally, we can calculate the pressure applied by the iron cube on the floor using the formula:

Pressure = Weight / Area

Pressure = 0.7742 N / 0.01 m^2 = 77.42 N/m^2

Therefore, the pressure applied by the iron cube on the floor is 77.42 N/m^2.