Question

3^x=7292^x=10247^x=1/343

Answer 1

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Answer 2

To solve the given equations, we can use logarithms. Let's solve each equation one by one:

1. $3^x = 1/343$

We can rewrite $1/343$ as $3^{-3}$, so the equation becomes:

$3^x = 3^{-3}$

Since the bases are the same, the exponents must be equal:

$x = -3$

2. $7292^x = 1/343$

We can rewrite $1/343$ as $7292^{-3}$, so the equation becomes:

$7292^x = 7292^{-3}$

Since the bases are the same, the exponents must be equal:

$x = -3$

3. $10247^x = 1/343$

We can rewrite $1/343$ as $10247^{-3}$, so the equation becomes:

$10247^x = 10247^{-3}$

Since the bases are the same, the exponents must be equal:

$x = -3$

In conclusion, the value of $x$ is -3 for all three equations.