Question

Средняя скорость передачи данных по некоторому каналу связи равна 30 Кбит/с. Определите, сколько понадобится секунд, чтобы передать по этому каналу 80 страниц текста, каждая страница которого содержит в среднем 128 символов, а информационный вес одного символа равен 8. ( с дано, и решением)

Answer 1

8 * 128 * 80 = 81920 (бит весит весь текст)Т.к. 1 байт = 8 битам, 1 кб = 1024 кб следовательно 1 кб =  8192 следовательно
81920 бита = 10 кб
10 / 30 = 1/3 (секунды)

Answer 2

Calculation of Time Required to Transmit Text Data

To determine the time required to transmit 80 pages of text, we need to calculate the total amount of data to be transmitted and then divide it by the transmission speed.

Given: - Transmission speed: 30 Kbps (Kilobits per second) - Number of pages: 80 - Average number of characters per page: 128 - Information weight of one character: 8 bits

To calculate the total amount of data to be transmitted, we can multiply the number of pages by the average number of characters per page and the information weight of one character:

Total data = Number of pages * Average number of characters per page * Information weight of one character

Total data = 80 * 128 * 8 bits

Now, we need to convert the total data from bits to kilobits:

Total data in kilobits = Total data / 1024

Finally, we can calculate the time required to transmit the data by dividing the total data in kilobits by the transmission speed:

Time required = Total data in kilobits / Transmission speed

Let's perform the calculations:

Total data = 80 * 128 * 8 bits = 81920 bits

Total data in kilobits = 81920 bits / 1024 = 80 kilobits

Time required = 80 kilobits / 30 Kbps

Time required to transmit 80 pages of text = 2.67 seconds.

Please note that the above calculations assume ideal conditions and do not take into account any overhead or latency in the transmission process.